**1. The problem statement, all variables and given/known data**

Find V(r), the electric potential due to an infinitely long cylinder with uniform charge density ρ and radius R.

Use V(r = 2R) = 0 as your reference point.

**2. Relevant equations**

E at r < R = ##\frac{(ρr)}{2ε_{0}}##

E at r > R = ##\frac{(ρR^{2})}{(2ε_{0}r)}##

**3. The attempt at a solution**

This is basically simple. Just integrate the electric fields to get voltage. The only problem is figuring out the limits of integration. I BELIEVE that if you have a nontrivial reference point outside of a cylinder, you will need to integrate from r to 2R for both inside and outside. So I did this:

$$V(r < R) = \int_r^R \frac{\rho r}{2ε_{0}}dr + \int_R^{2R} \frac{\rho r}{2\epsilon_{0}}dr = \frac{\rho}{4\epsilon_{0}}(4R^{2} – r^{2})$$

$$V(r > R) = \int_r^{2R} \frac{\rho R^{2}}{2\epsilon_{0}r}dr = \frac{\rho R^{2}}{2\epsilon_{0}}ln(\frac{2R}{r})$$

Does this look right?

http://ift.tt/1omyTeN