# Solving for current between 2 nodes

1. The problem statement, all variables and given/known data

Assume that I = 22mA , V = 6.0V , and R = 350Ω. Determine the current between B and D using the superposition principle.

2. Relevant equations

V=IR
Superposition Principle
G=1/R
Voltage and Current dividers
KCL, KVL

3. The attempt at a solution

I_BD = I_BD’ + I_BD”

Shorting the voltage source first, I have:

R_eq of resistors now in parallel = 100*300/(100+300) = 75

Applying the current divider to the remaining circuit, I have:

I_BD” = -0.022 * 300/825 = -0.008

(I also solved this using mesh analysis and got the same answer)

Now replacing the current source with an open circuit, I have:

R_eq from A to C to D to B = 750

Combining that with the 300 Ohm resistor it is now in parallel with, then with the 100 Ohm resistor in series, I have:

R_eq = 314.3

Solving for total current with V=IR, I_total = 0.019 A

Applying the current divider:

I_BD’ = 0.019*300/1050 = 0.0054 A

Combining I_BD’ and I_BD”, I_BD = -0.0026 A which is incorrect. Not exactly sure what I’m doing wrong here.

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