**1. The problem statement, all variables and given/known data**

A person kicks a soccer ball with an intial velocity directed 53 degrees above the horizontal. The ball lands on a roof 7.2 m high. The wall of the building is 25m away, and it takes the ball 2.1 seconds to pass directly over the wall. Calculate the intial velocity of the ball an its horizontal range.

**2. Relevant equations**

this is for horizontal motion

Vix=[itex]\Delta[/itex]x/[itex]\Delta[/itex]

this is for vertical motion

Vfy=Viy+ay([itex]\Delta[/itex]t)

[itex]\Delta[/itex]y=viy[itex]\Delta[/itex]t+1/2ay([itex]\Delta[/itex]t)^2

Vfy^2=Viy^2+2ay[itex]\Delta[/itex]y

[itex]\Delta[/itex]y=Vfy[itex]\Delta[/itex]t-1/2ay([itex]\Delta[/itex]t)^2

**3. The attempt at a solution**

Okay hi everyone this is my first post! Well okay i dont understand the part about how it takes 2.1 seconds to go over the wall because in most of the questions i have done they give total time.

http://ift.tt/1c9Zn0p