Newton’s law question (pulley)

1. The problem statement, all variables and given/known data
Block A has a weight of 400N and block B has a weight of 100N. The coefficient of friction between all surfaces of contact are μs = 0.7 and μk = 0.2.
Knowing that θ = 60°, determine the acceleration of block A and the tension in the cord. Assume block A is moving downwards.
I know I should be solving for the acceleration but I figured if I get the tension I could use ∑F = ma on block B to get the acceleration there and that would be the same acceleration on block A.

2. Relevant equations

∑F = ma

3. The attempt at a solution
took the inclined plane and it’s normal as the axis and used Newton’s equation on the perpindicular axis to get the normal (N – Wcosθ = 0) and got N = 200N. Then used the plane’s axis at the moment the tension force equals the static friction (Wsinθ – 2T – μsN = 0) but I got 103.7N as the answer when it should be 127N and I don’t know what my mistake is.

Attached Images
File Type: jpg 20140619_165520.jpg (29.0 KB)

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