# Ideal Gas/Work Done by Water Problemq

1. The problem statement, all variables and given/known data

You have a sealed container with 2 kg of water (molar mass: 18 g/mol, density: 1000 kg/m 3). The lid on the the container is very light, and the container side walls are very tall, like a tall graduated cylinder. You start with the water at room temperature 25 degrees C and boil all the water until you get to 200 degrees C. What is the Work done by the water molecules?
Select one:
a. 234 kJ
b. 334 kJ
c. 434 kJ
d. 534 kJ

2. Relevant equations

PV=nRT
P1V1/T1=P1V2/T2
p(deltaV)=nR(deltaT)
-deltaW=deltaE

3. The attempt at a solution

I tried solving for p(deltaV) which is equal to the change in energy which could then be used to find work done but never could get one of those answers. I did this by starting with PV=nRT.
P=100,000 Pa
V=?
n=111.111
R=8.314
T= 25+273.15=298.15
Plug those in to get V=2.75
Plug that into P1V1/T1=P2V2/T2 to get V2=4.36
So then P(deltaV) should equal 100,000 (4.36-2.75)=161000 which equal -deltaW. I don’t really know where to go from here or what I’m doing wrong.

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