forces in equilibrium

We had a lab 2 weeks ago that dealt with predicting the "known unknown" masses (we know it’s 250g and we have to experiment to try and get to 250g as close as possible) within a pulley system.

All three trials we had for part 1, where the known unknown was placed in the middle, we only needed to calculate for its y-component. I was just wondering why didn’t we need to calculate the x-component?

Leave a Reply

Name *
Email *