A 10.0-μF capacitor is charged by a 10.0-V battery through a resistance R. The capacitor reaches a potential difference of 4.00 V at the instant 3.00 seconds after charging begins
1.) Find R
2.) Find the current at t=3.00 seconds after charging begins.
2. Relevant equations
3. The attempt at a solution
so obviously I know how to find current but I need to find resistance and I cannot use R=V/I because it is non-ohmic! what do I do?