**1. The problem statement, all variables and given/known data**

A 1kg box of Aluminum initially at 22C is warmed at P=1atm so that its T increases to 40C. Find

a) The work done on the system

**2. Relevant equations**

W= -∫PdV

**3. The attempt at a solution**

The pressure is constant at 101,300Pa

D=m/V

So V=m/D

D of Al at room temp = 2700kg/m^3

Therefore

[itex]W= -101,300Pa \frac{1kg}{2700kg/m^{3}}(1+24×10^{-6}(18))^{3}[/itex]

Where ΔT=18 and 24×10^-6 is the linear coefficient of expansion of Aluminum.

= -37.6J

Not the right answer, it should be around 48mJ. I can’t see what I’m doing wrong here.

http://ift.tt/1d4Jgip