The ammonia molecule (NH3) has a dipole moment of 5.0×10−30C⋅m. Ammonia molecules in the gas phase are placed in a uniform electric field E⃗ with magnitude 1.0×106N/C.
What is the change in electric potential energy when the dipole moment of a molecule changes its orientation with respect to E⃗ from parallel to perpendicular?
2. Relevant equations
V = U/q
ΔU = -integral([itex]qE dl[/itex])
ΔV = -integral([itex]E dl[/itex])
E(r) = -∇V(r)
I have no idea what the upside down delta is…
3. The attempt at a solution
I don’t even know where to start. :confused: