Consider the three charges in the figure below, in which d = 4.7 cm, q = 11 nC, and the positive x-axis points to the right. What is the force Fvec on the 5 nC charge? Give your answer as a magnitude and a direction.
2. Relevant equations
3. The attempt at a solution
First I found the distance between +5 and 11.
Then the magnitude: .000164
The the magnitude of +5, -5 –> .00025 (Horizontal component)
cos 57.45 = x/.000164 = 8.823X10^-5 (Vertical component of line)
sin 57.45 = x/.000164= 1.3824×10^-4 (Horizontal component of line)
Add horizontal components and use that and vertical to make a triangle and find the third side.
So my answer is incorrect, can someone help me out please. Thank you.