I haven’t done many problems of this nature so there are a few steps in my working that i’d like to check are acceptable/agree with what the question implies.

**1. The problem statement, all variables and given/known data**

A water tower is a familiar sight in many towns. The purpose of such a tower is to provide storage capacity and to provide sufficient pressure in the pipes that deliver the water to customers. The drawing (see attached) shows a reservoir that contains [itex]5.25[/itex]x[itex]10^{5} kg[/itex] of water. The reservoir is vented to the atmosphere at the top. Find the gauge pressure that the water has at the faucet in house A and house B. Ignore the diamter of the delivery pipes.

**2. Relevant equations**

**3. The attempt at a solution**

My first concern is that last sentence. Is it correct to assume that the pressure at the water tower is simply equal to it’s weight? I proceeded under that assumption…

[itex]P_{1} + \frac{1}{2}\rho v^{2}_{1} + \rho g y_{1} = P_{2} + \frac{1}{2}\rho v^{2}_{2} + \rho g y_{2}[/itex]

I’m using [itex]g = 10ms^{-2}[/itex] to keep the numbers neat.

[itex]v_{1} = v_{2} = 0[/itex]

[itex]P_{B} > P_{WT}[/itex] Pressure at faucet B is greater than the pressure at the water tower, since it is lower.

[itex]P_{WT} + \rho g y_{WT} = P_{B} + \rho g y_{B}[/itex]

[itex]P_{WT} + \rho g y_{WT} – \rho g y_{B}= P_{B}[/itex]

(I’ve plugged in the numbers, but i’m more interested in whether or not my method is correct)

[itex]P_{B} = 5327000 Pa[/itex]

For faucet A;

[itex]P_{A} > P_{B} > P_{WT}[/itex] Due to being lowest of all.

[itex]P_{WT} + \rho g y_{WT} = P_{A} + \rho g y_{A}[/itex]

[itex]P_{WT} + \rho g y_{WT} – \rho g y_{A}= P_{A}[/itex]

A’s height is 0m.

[itex]P_{A} = P_{WT} + \rho g y_{WT} – 0[/itex]

[itex]P_{A} = 5400000 Pa[/itex]

My answers do agree with the inequalities I was expecting, but that first assumption is troubling me.

Is this okay?

Thanks for taking the time to read!

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