Work and Kinetic Energy

1. The problem statement, all variables and given/known data
An ice block is being pushed through a displacement d→=(15m)i -(12m)j along an embankment with rushing water. It exerts F→=(210N)i -(150N)J on block. How much work on block does force do?

2. Relevant equations
W=Fxd
Pythogoreum equation
a^2 +b^2= c^2

3. The attempt at a solution
I drew i and j coordinates for both displacement vector and force vector. I calculated
d→=15^2 + 12^2= c^2
d→=c=19.21m
I used same for F→
(210N)^2 + (150N)^2 = c^2
c=258.07 N
W=Fxd
(258.07N)* (19.21m) = 4957.52 J
I think I might have set it up wrong.

http://ift.tt/1jIAMTn

Leave a comment

Your email address will not be published.


*


Show Buttons
Hide Buttons