Wheastone Bridge

1. The problem statement, all variables and given/known data
Compute i1 and i2 in Figure a). R3 = R4 = 6Ω, and R5 = R6 = 12Ω.

2. Relevant equations

KVL and KCL

3. The attempt at a solution

Since R3 / R5 = R4 / R6 , it’s a Wheastone Bridge and i2 = 0, and i1 = [itex]\frac{20}{9}[/itex] A.

But my question is, why circuit in Figure b) is not equivalent to circuit in Figure a) when a) is a Wheastone Bridge?

Attached Images
File Type: png Diagram1.png (30.3 KB)

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