# Wheastone Bridge

**1. The problem statement, all variables and given/known data**

Compute i1 and i2 in Figure a). R

_{3}= R

_{4}= 6Ω, and R

_{5}= R

_{6}= 12Ω.

**2. Relevant equations**

KVL and KCL

**3. The attempt at a solution**

Since R_{3} / R_{5} = R_{4} / R_{6} , it’s a Wheastone Bridge and i_{2} = 0, and i_{1} = [itex]\frac{20}{9}[/itex] A.

But my question is, why circuit in Figure b) is not equivalent to circuit in Figure a) when a) is a Wheastone Bridge?

http://ift.tt/1oxgYRv

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