**1. The problem statement, all variables and given/known data**

A mass of 100 kg is suspended by two ropes that make an angle of 60 degrees to the horizontal. If a horizontal pull of 200N, in a plane perpendicular to the plane of the other forces is applied find the tensions in the ropes after equilibrium has occurred.

**2. Relevant equations**

Component Method

**3. The attempt at a solution**

T1cos60=T2cos60

T2=(T1cos60)/(cos60)

Fx=-T1cos60+T2cos60

Fy=T1sin60+T2sin60-Fg

Sub in T2 into equation

Fy=T1sin60+T2sin60-Fg

= (T1sin60)+((T1cos60)/(cos60))(sin60)

= T1sin60+T1(0.866)

=T1(sin60+0.866)=(100)/(9.8)

T1=T2=565.8

Can someone please tell me if I did this right?

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