Two capacitors are connected in parallel

1. The problem statement, all variables and given/known data
Two capacitors (C1 = 9.3 μF and C2 = 29 μF) are connected in parallel across a 12 V battery.
a) Find the equivalent capacitance of the two capacitors.
Ceq=C1+C2=9.3+29=38.3μF

After some time has passed (use for rest of problem):
b) How much current flows in this circuit?
____A

c) Find the charge stored on each capacitor.
Q1 =____μC
Q2 =____μC

d) Calculate the potential energy stored by each capacitor:
U1 =____μJ
U2 =____μJ

2. Relevant equations

C=Q/V

U=(1/2)*C*V^2

I=dq/dt

3. The attempt at a solution

part b is where i got stuck. I dont know how to find the current flowing in the circuit if the time wasnt given to me. Current is a function of (dq/dt).
I know after for very long time, the current flow into the capacitor will be zero since the battery used all of its energy to charge the capacitor, therefore no current flow.
Can someone help me out? Thank you so much

http://ift.tt/PuV31e

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