3. My attempt at solution
Hi :tongue: Here is the question I am looking at http://ift.tt/1oDIAIb
I take the datum as the fixed point so there is no kinetic energy to start with.
There is potential energy of mgx which is (4kg)(9.81m/s^2)(0.5) = 19.62 Joules
Kinetic energy is (1/2)mv^2, therefore 4v^2 as mass is 4kg
So total mechanical energy is (kinetic energy) + (potential energy) = 5.886J + 4v^2
Not sure if that is correct as I find this very confusing, and can’t get an idea of how to answer the question that asks for the maximum distance that the particle falls