Time Dependent Current in a Wire

1. The problem statement, all variables and given/known data

Problem is attached

2. Relevant equations

A formula sheet is also attached

3. The attempt at a solution

flux=[itex]\int[/itex]B dA from .31m to .82
B=u I(enclosed)/2(pi)(d)
d=x
dA=dx L
so ∫ (u)(I)(L)dx / 2(pi)(x) from .31m to .82m remember x=d in the pic. My answer is 3.9687e-7 and its wrong

integral came out to be (u)(I)(L)/2pi (ln(.82) – ln(.31))
u=4(pi)e-7
I=4A

Attached Images
File Type: png Prob.png (56.9 KB)
File Type: png formula.png (17.0 KB)

http://ift.tt/1f8yBky

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