# Thin Lens – Object Distance

**1. The problem statement, all variables and given/known data**

Now consider a diverging lens with focal length f=−15cm, producing an upright image that is 5/9 as tall as the object.

What is the object distance? You will need to use the magnification equation to find a relationship between s and s′s′. Then substitute into the thin lens equation to solve for s.

**2. Relevant equations**

1) M = -s^{‘}/s

2) 1/s+1/s^{‘}=1/f

**3. The attempt at a solution**

using equation 2 I solved for s^{‘} then subsituted that into equation 1 and solved for s and from that put it back into equation s and solved for s and ended up with the answer of -65/3.

However this was the wrong answer and do not know what I did wrong.

http://ift.tt/1leafhu

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