Now consider a diverging lens with focal length f=−15cm, producing an upright image that is 5/9 as tall as the object.
What is the object distance? You will need to use the magnification equation to find a relationship between s and s′s′. Then substitute into the thin lens equation to solve for s.
2. Relevant equations
1) M = -s‘/s
3. The attempt at a solution
using equation 2 I solved for s‘ then subsituted that into equation 1 and solved for s and from that put it back into equation s and solved for s and ended up with the answer of -65/3.
However this was the wrong answer and do not know what I did wrong.