# Thermodynamics – volumes

**1. The problem statement, all variables and given/known data**

A hollow aluminum cylinder 2cm deep has an internal capacity of 2L at 20C. It is completely filled with turpentine and then slowly warmed to 80C.

a) How much turpentine overflows?

b)If the cylinder is then cooled back to 20 C how far below the cylinder’s rim does the turpentine recede?

**2. Relevant equations**

Vnew=Vold(1+αΔT)^3

**3. The attempt at a solution**

I’m so confused. I just plugged and chugged into the formula.

It seems that the solutions manual uses the formula for the Al container, getting 2.0087L, which I follow. Then for the turpentine, they just do

2L(1+αΔT)=2.108L

So they do NOT cube it. What am I missing here? Why aren’t they cubing the turpentine?

http://ift.tt/1f5YTCL

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