Assume that Vs = 10V , R1 = 1.7Ω , and R2 = 0.50Ω. Find the current I in the figure using the superposition principle.
2. Relevant equations
Current and voltage dividers
3. The attempt at a solution
I = I’ + I”
First replacing the current source with an open circuit, I have:
(1.7+0.50)*I’ = 10 – 2I’ using KVL
Solving, I’ = 2.38 A
Now replacing the voltage source with a short, I use the current divider to get:
-I” = 3*0.5/(1.7+0.5) = 0.682 A
I” = -0.682 A
I = 2.38 – 0.682 = 1.7 A, which is incorrect.
EDIT: Should I have left the dependent source as 2I and solved for I in the final equation, or am I doing something else wrong?