[b] Vector A is 100m East at 0°, Vector B is 300m south and vector c is 150 meters southwest and vector D is 200 meters north west. There are two angle measurements given. I dont know how to upload the exact picture but if you go to http://ift.tt/1glYC3c and find the exact problem, the picture is on there as well as the answer. I dont know how they got to that answer. Please help.

[b]3.A_x=100m

A_y=0m

B_x=0m

B_y=300m

C_x=150cos(120)=-75m

C_y=150sin(120)=129.9 m

d_x=200cos(75)=51.8 m?

d_y=200sin(75)=193.2

Im not sure how to get the correct angle measurements for vector d. I tried to figure it out from the angles given but it was very confusing.

to find the resultant I did F_x=100+0+0+-75=25m

F_y=193.2+129.9+300+0=569.1m

[itex]/sqrt{F_x^2+F_y^2}

i got 569.6m

and tan^-1(569.1/25)=87.5°

Where did I go wrong? I think it is the angle measurements I put in but Im not sure how to get the correct measurements.

http://ift.tt/1iZqCtJ