The Clapeyron cycle efficiency is similar to the Carnot cycle except that two adiabatic paths are replaced with isobaric processes
a) based on the above information, draw a Clapeyron cycle.
b)Derive the efficiency of the reversible Clapeyron cycle
2. Relevant equations
3. The attempt at a solution
part a) see attachment
b) I really dont know where to start with this,
I am thinking of using QL=nCp(Td-Ta) & QH=nCp(Tc-Tb) as a starting point.
Any help would be greatly appreciated.