Reversible Clapeyron cycle efficiency

1. The problem statement, all variables and given/known data
The Clapeyron cycle efficiency is similar to the Carnot cycle except that two adiabatic paths are replaced with isobaric processes

a) based on the above information, draw a Clapeyron cycle.

b)Derive the efficiency of the reversible Clapeyron cycle

2. Relevant equations

e=1-(QL/QH)
3. The attempt at a solution

part a) see attachment

b) I really dont know where to start with this,

I am thinking of using QL=nCp(Td-Ta) & QH=nCp(Tc-Tb) as a starting point.

Any help would be greatly appreciated.

Attached Files
File Type: pdf TD Problem set 1_0002.pdf (60.8 KB)

http://ift.tt/1bJKSjw

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