# Reversible Clapeyron cycle efficiency

**1. The problem statement, all variables and given/known data**

The Clapeyron cycle efficiency is similar to the Carnot cycle except that two adiabatic paths are replaced with isobaric processes

a) based on the above information, draw a Clapeyron cycle.

b)Derive the efficiency of the reversible Clapeyron cycle

**2. Relevant equations**

e=1-(QL/QH)

**3. The attempt at a solution**

part a) see attachment

b) I really dont know where to start with this,

I am thinking of using QL=nCp(Td-Ta) & QH=nCp(Tc-Tb) as a starting point.

Any help would be greatly appreciated.

http://ift.tt/1bJKSjw

## Leave a comment