Reaction forces due to imbalance of a shaft

1. The problem statement, all variables and given/known data

The shaft carries two particles of mass m, and rotates about the z-axis with the constant angular velocity ##\omega##. Determine the x- and y-component of the bearing due to imbalance.

3. The attempt at a solution

Rotation only around the ##z-##axis so ##\omega _{x}=\omega _{y}=0## and ##\boldsymbol{\omega }=\omega \boldsymbol{\hat{k}}##. Since ##\dot{\omega}=0## we have:
##\left\{\begin{matrix}
\sum M_{x}=I_{yz}\omega^2\\ \sum M_{y}=-I_{xz}\omega^2
\\

\end{matrix}\right.##

I have trouble now. Is it correct that for ##M_{y}##, only forces acting perpendicular to y-axis that should be accounted for? We also see that the intersection of points of the ##xz-##plane and the two sphere’s are none so that means that ##I_{xz}=0##(Is this even correct??). And ##I_{yz}=\overline{I}_{yz}+md_{y}d_{z}=0+mR\frac{L}{3}-mR\frac{2L}{3}##

http://ift.tt/1gWmafO

Leave a comment

Your email address will not be published.


*


Show Buttons
Hide Buttons