A person is pushing a box on a floor with a 250 N force. The box is moving at a constant speed over 12.75 m.
(a) What quantity of work does the person do on the box?
(b) What quantity of word does friction do?
(c) What is the total work done?
2. The attempt at a solution
(a) W = F * d * cosx = (250 N)(12.75 m)(cos0) = 3187.5 Joules
(b) W = F * d * cosx = (250 N)(12.75 m)(cos180) = -3187.5 Joules
(c) Total work = Wperson + Wfriction = 3187.5 J + (-3187.5 J) = 0