An electron is fired at a speed vo = 5.6 ✕ 10^6 m/s and at an angle θo = -40° between two parallel conducting plates that are D = 2.5 mm apart, as in Figure P16.66. The voltage difference between the plates is ΔV = 103 V.
2. Relevant equations
3. The attempt at a solution
I tried finding acceleration with (ΔV/D)(q/m) or 103/.0025 * 1.6e-19/9.11e-31
I found Vy with 5.6e6sin(40)
Then i used vyf^2 = vyo^2 + 2aΔy to solve for Δy
then i subtracted my answer from .00125 m and got .54 mm, but the website says i’m off by more than 10%.
I haven’t tried part B yet because i could have acceleration wrong and that will just mess up both answers.