Parallel plate conductor

1. The problem statement, all variables and given/known data

An electron is fired at a speed vo = 5.6 ✕ 10^6 m/s and at an angle θo = -40° between two parallel conducting plates that are D = 2.5 mm apart, as in Figure P16.66. The voltage difference between the plates is ΔV = 103 V.

2. Relevant equations

3. The attempt at a solution

I tried finding acceleration with (ΔV/D)(q/m) or 103/.0025 * 1.6e-19/9.11e-31

I found Vy with 5.6e6sin(40)

Then i used vyf^2 = vyo^2 + 2aΔy to solve for Δy

then i subtracted my answer from .00125 m and got .54 mm, but the website says i’m off by more than 10%.

I haven’t tried part B yet because i could have acceleration wrong and that will just mess up both answers.

http://ift.tt/1jV5XXP

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