Block A has a weight of 400N and block B has a weight of 100N. The coefficient of friction between all surfaces of contact are μs = 0.7 and μk = 0.2.
Knowing that θ = 60°, determine the acceleration of block A and the tension in the cord. Assume block A is moving downwards.
I know I should be solving for the acceleration but I figured if I get the tension I could use ∑F = ma on block B to get the acceleration there and that would be the same acceleration on block A.
2. Relevant equations
∑F = ma
3. The attempt at a solution
took the inclined plane and it’s normal as the axis and used Newton’s equation on the perpindicular axis to get the normal (N – Wcosθ = 0) and got N = 200N. Then used the plane’s axis at the moment the tension force equals the static friction (Wsinθ – 2T – μsN = 0) but I got 103.7N as the answer when it should be 127N and I don’t know what my mistake is.