Kinetic energy and Work

1. The problem statement, all variables and given/known data
A 100 kg refrigerator is on rest on the floor.How much work is needed to move the refrigerator at a constant speed for 6 m along with a floor friction force of 200 N ?

2. Relevant equations
I used ΔK = W(Fg)+ W (N) + W(f)+ W(T) =0
and W(Fg)+ W (N) = 0
so W(T)=-W(f)=f* Δl
3. The attempt at a solution

The needed work is W(K)= 1200 J

Is it correct ??

Leave a comment

Your email address will not be published.


Show Buttons
Hide Buttons