A car is moving with a speed of 32.0 m/s. The driver sees an accident ahead and slams on the brakes, giving the car an acceleration of -3.50 m/s2. How far does the car travel after the driver put on the brakes before it comes to a stop?
2. Relevant equations
3. The attempt at a solution
How would this problem be solved? Does it require two steps?
Is Vf=0m/s and Vi= 32 m/s?
Because if that’s the case, wouldn’t I use the formula a=vf-vi/t
-3.5 m/s2=(0 m/s – 32 m/s)/t
-3.5 m/s2 = (-32 m/s)/t
t= -32 m/s/-3.5 m/s2
t= 9.14 s
Then to find distance, use s=d/t, rearrange as d=s*t
d=32 m/s*9.14 s