# Kinematics

**1. The problem statement, all variables and given/known data**

A particle moving at 10 m/s reverses its direction to move at 20 m/s in the opposite direction. If its acceleration is -10 m/s

^{2}, what is the total distance that it travels?

A) 15 m

B) 20 m

C) 25 m

D) 30 m

**2. Relevant equations**

a = Δv/t

v = Δx/t

**3. The attempt at a solution**

In one direction:

time = velocity/acceleration = 10/10 = 1 s

velocity = distance/time = velocity * time = distance

distance = 10 m/s * 1s = 10 m

In the reverse direction:

acceleration = velocity/accelertion; time = velocity/acceleration

time = 20 m/s/10 m/s^{2} = 2 s

velocity = distance/time; distance = velocity * time = 20 m/s * 2 = 40 m

Distance traveled:

40 m + 10 m =50 m

I realize my final answer did not come out to be any of the choices above but am not sure of any other correct way to approach this problem.

http://ift.tt/1cDwfcr

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