A newly discovered asteroid orbits at twice the Earth-Sun distance. Find its period of orbit (in years).
2. Relevant equations
I know that I’m supposed to use Kepler’s third law to determine this.
T2 = Kr3
K = 4∏2/GM
and the Earth-Sun distance is of course 1 Au
3. The attempt at a solution
I know that the answer should be √8 or about 2.83 years I just don’t know how to get there. So frustrating because I know that this is a simple question.
Could it be that K = 1, and R=2 therefore R3 = 8?