**1. The problem statement, all variables and given/known data**

Determine the voltage drop across R_{1}

R1 = 770 , R2 = 630 , and R3 = 470 .

The equivalent resistance is 816Ω

**2. Relevant equations**

V = IR

**3. The attempt at a solution**

1.) I find the total current of the circuit:

V = IR -> I = V/R

I = 12v/816Ω = 0.015A

2.) I then find the voltage drop across that particular resistor:

V = IR

V = 0.015A * 770Ω

V = 11.32v

This has been confirmed to be the wrong answer.

I don’t understand what I am doing incorrectly.

Could someone please help me understand my mistake (where ever it may be)?

Many Thanks!

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