What will be the irradiance (power per unit area) in the image, if the Sun’s irradiance at the sea level is I = 500W/m^2
Lens is 200mm f
Sun is 150×10^9 m away
Diameter of sun is 1.4×10^9 m
2. Relevant equations
3. The attempt at a solution
I know that at the lens the irradiance will be the same i.e. 500W/m^2 but at the image the irradiance will be magnified. I’m not sure how to get there though.
I know an image of the sun will be .2m from the lens and the diameter of the image will be .00187m because M=di/do = .2m/150×10^9 = 1.333X10^-12 and 1.333×10^-12 multiplied by the diameter of the sun is .000187m.