Two capacitors, C1 = 4μF and C2 = 9μF, are connected in series with a 30 V battery. The battery is removed and the plates of like sign are connected. Find the initial and final energies for each capacitor.
2. Relevant equations
Ceq = ∑Ci ( don’t know how to note it on the computer) –> in parallel
I think that’s about it..?
3. The attempt at a solution
1) find ceq ( in series) =>2.77uF
2)Find totaly charge ( same on both cause in series) =>93.077uC => Get initial energy from this (????)
3)Voltage on C1 => q/c => 20.78 V
4)Voltage on C2 => 1/c => 9.23 V
5)After they are reconnected, it needs to reach equilibrium ( I think?) So my total charge is
2*83.077 = 166.154 uC ??
Sooooo then my voltage on capacitor 1 would be 166.154/13 => 12.78V ( approx.)
6)Q1 final => c*v => 4uF*12.78 =>51uC
7)Q2 final => c*v => 9uF*12.78 =>115.02uC
9) Energy Final on 1 => q^2/2C => 325.125 J
10) Energy Final on 1=> q^2/2C=> 735 J