Slick is skiing down a 27 degree slope (above horizontal) into a headwind (parallel to the slope) of 8N. His mass is 78Kg. The coefficient of friction between the snow and the skis is 0.11. What is the resultant force? If the coefficient of friction increases to 0.13, how much additional force will Slick have to add to maintain the same resultant force, assuming that the added force is parallel to the slope? How much additional force will he have to add to maintain the same resultant force in the added force is 45 degrees to the ski slope (ie. he pushes backward with his pole)? How can he potentially reduce the force that is opposing his progress down the hill

**2. Relevant equations**

I don’t really know what to put in this?

My attempt:

I found the resultant force, which I calculated to be 264.4N? I also came up with 13.5N, for the additional force he would have to add to maintain the same resultant force. Its so late, and I want to be done. But I am having a hard time trying to figure out the equation for how much force hed have to add is the angle changed to 45 degrees?

Any help at all would be greatly appreciated!

http://ift.tt/1j1ltRs