Imagine that a bullet is shot vertically into the air with an initial

1. The problem statement, all variables and given/known data

Imagine that a bullet is shot vertically into the air with an initial speed of 9800 m/s. If we ignore air friction, how high will it go?

vi = 9800 m/s
h = ?

2. Relevant equations

v2 = vi2 + 2aΔy
Ki = Ui –> 1/2mv2 = mgh

F = (Gm1m2)/r

3. The attempt at a solution

Attempt 1

v2 = vi2 + 2aΔy
0 = (9800 m/s)2 + 2(-9.8 m/s2)(Δy)
Δy = 4,900,000 m

Attempt 2

1/2mv2 = mgh
h = 4,900,000 m

Neither of these equations worked, so I tried using gravitational equations, but I couldn’t figure it out.

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