# Ideal Gas/Work Done by Water Problemq

**1. The problem statement, all variables and given/known data**

You have a sealed container with 2 kg of water (molar mass: 18 g/mol, density: 1000 kg/m 3). The lid on the the container is very light, and the container side walls are very tall, like a tall graduated cylinder. You start with the water at room temperature 25 degrees C and boil all the water until you get to 200 degrees C. What is the Work done by the water molecules?

Select one:

a. 234 kJ

b. 334 kJ

c. 434 kJ

d. 534 kJ

**2. Relevant equations**

PV=nRT

P1V1/T1=P1V2/T2

p(deltaV)=nR(deltaT)

-deltaW=deltaE

**3. The attempt at a solution**

I tried solving for p(deltaV) which is equal to the change in energy which could then be used to find work done but never could get one of those answers. I did this by starting with PV=nRT.

P=100,000 Pa

V=?

n=111.111

R=8.314

T= 25+273.15=298.15

Plug those in to get V=2.75

Plug that into P1V1/T1=P2V2/T2 to get V2=4.36

So then P(deltaV) should equal 100,000 (4.36-2.75)=161000 which equal -deltaW. I don’t really know where to go from here or what I’m doing wrong.

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