How the tension is calculated?

A massless rod of length L attached to mass m and with axle to cart of mass M. The cart has a shape of equilateral triangle (edge L). the cart is at rest and its center of mass is above x=0 and a rod is perpendicular to the ground. the cart is free to move without friction. at time t=0 the mass m is released and starts to fall to the left. at time t=τ the rod is parallel to the ground. Why the tension from the stick is T=mv^2/L=2mg and not T=mv^2/L=mg?

Attached Images
File Type: jpg 2.JPG (21.8 KB)

http://ift.tt/1kfK0G3

Leave a comment

Your email address will not be published.


*


Show Buttons
Hide Buttons