Basically, I need to calculate the mass of the pulley and friction using data that I collected.
2. Relevant equations
I was given: (m1 – m2)g = (m1 + m2 + mp)a + f
3. The attempt at a solution
For the first part, I collected data using a sensor to find the acceleration. I kept the total mass attached to each cup on each side of the machine constant but changed the difference in their masses by 10g each run.
After 6 runs, I plotted my data of Fnet vs Acceleration. Fnet is (m1 – m2)g (I converted g into dynes). When I get my slope, the lab manual says that i should "expect our plot of (m1 – m2)g vs a to have a slope larger than (m1 – m2)g by an amount equal to the effective mass of the pulley mp and a positive intercept equal to the frictional force f"
My equation turned out to be y = 143.28x + 323.24 (i used best fit line).
This means 143.28 = m1 + m2 + mp
In which case mp= 28.5g right?
Then the force of friction should = 323.4 right?
Is the unit in dynes?
For part b, did the same procedure but kept the net force constant instead of the total mass. I gathered my data and plotted
1/a vs [I]m1 + m2[I]
I got y = 0.0002x + 0.0059 as my best fit line
Now I have to use this equation to find the force of friction
1/a = ((m1 + m2) )/((m1-m2)g-f) + mp/((m1-m2)g-f)
But i get 4950 which I believe is in Netwons and that would be too much considering 323 dynes = 0.00323 newtons