**1. The problem statement, all variables and given/known data**

A ray is deflected by 2.37cm by a piece of acrylic. Find the thickness

*t*of the acrylic if the incident angle is 50.5 degrees.

**2. Relevant equations**

n1sinΘ1 = n2sinΘ2

**3. The attempt at a solution**

n of acrylic is 1.5. Therefore, the refracted angle is 30.958 degrees. ( 1(sin(50.5)) = 1.5(sin(θ)) )

I’m not sure if I can make a triangle within the acrylic that is above the ray line where one angle is 50.042, one is 90, and the other is 30.958 and use 2.37cm as on side of the triangle.

**1. The problem statement, all variables and given/known data**

**2. Relevant equations**

**3. The attempt at a solution**

http://ift.tt/1ig3A1Q