Two charged objects are separated by a distance of L=0.4650 m as shown in the diagram.
Object Q1 has a charge of +5.250 nC. Object Q2 has a charge of +2.960 nC.
A) What is the magnitude and direction of the electric field at Point A, which is located a distance d=0.09300 m to the right of Object Q1?
B) If you were to place an electron at Point A, what would be the magnitude and direction of the force on the electron?
2. Relevant equations
E= k (q/r^2)
F= (k*Q1*Q2)/ (r^2)
3. The attempt at a solution
A) [ (8.99E9) ((5.25E-9)/(.09300^2) ] – [ (8.99E9) ((2.96E-9)/(.372^2) ]=
= 5265 N/C = 5.265E3 N/C to the right THIS ANSWER IS CORRECT
B) The charge on an electron is -1.6E-19. I am also assuming that i will need Coulombs Law to solve.
[(8.99E9)(5.25E-9)(2.96E-9)] / (.4650) =.64610E-7 to the left
This is not the right answer and I’m not sure why. AM i even using the right formula?
Any help would be greatly appreciated. Thanks!