# Force and Work problem

I was given the problem:

A single force acts on a 3.6 kg particle-like object in such a way that the position of the object as a function of time is given by x = 4.1t – 0.64t2 + 2.0t3, with x in meters and t in seconds. Find the work done on the object by the force from t = 0 to t = 8.1 s.

I know that W= integral of Fx, but how do I find Fx?

http://ift.tt/1srtHL9