**1. The problem statement, all variables and given/known data**

A 10.0-μF capacitor is charged by a 10.0-V battery through a resistance

*R*. The capacitor reaches a potential difference of 4.00 V at the instant 3.00 seconds after charging begins

1.) Find

*R*

2.) Find the current at t=3.00 seconds after charging begins.

**2. Relevant equations**

i=[itex]\frac{dq}{dt}[/itex]=-[itex]\frac{CV_{ab}}{RC}[/itex]*e*[itex]^{-t/RC}[/itex]

**3. The attempt at a solution**

so obviously I know how to find current but I need to find resistance and I cannot use R=V/I because it is non-ohmic! what do I do?

http://ift.tt/1dRY7Ku