Finding F1

1. The problem statement, all variables and given/known data

There are two forces on the 2.80 kg box in the overhead view of the figure but only one is shown. For F1 = 10.9 N, a = 10.2 m/s2, and θ = 34.9°, find the second force (a) in unit-vector notation and as (b) a magnitude and (c) a direction. (State the direction as a negative angle measured from the +x direction.)

I’m not sure if this link will work, but here’s the picture: http://ift.tt/1bYSsVd

2. Relevant equations

∑F=ma
∑F=F1+F2…+

3. The attempt at a solution

Ok so I’ve been stuck on this one for a while. I started out finding the sum of the forces:
∑F=(2.8kg)(10.2m/s2)=28.56 N

Then I tried solving for F2:
28.56N=10.9N+F2
F2=17.66

Then I found the x and y components of the acceleration:
ax=10.2*sin(34.9)=5.84m/s2
ay=10.2*cos(34.9)=8.37m/s2

Could you multiply ax and ay by the mass and get the F1x and F1y?
I’m so confused, could someone please help guide me through this problem?

http://ift.tt/1lF7zGf

Leave a comment

Your email address will not be published.


*


Show Buttons
Hide Buttons