Find total E of muon using time dilation

1. The problem statement, all variables and given/known data

An Ω particle has rest energy 1672 MeV and mean lifetime 8.2*1011 s. It is created and decays in a particle track detector and leaves a track 24 mm long. What is the total energy of the particle?

2. Relevant equations

E=[itex]\frac{mc^2}{\sqrt{1-(\frac{v}{c})^2}}[/itex]

t=t0[itex]\sqrt{1-(\frac{v}{c})^2}[/itex]

Rest E=mc2

3. The attempt at a solution

Because Rest E=mc2 I know that:

E=[itex]\frac{1672 MeV}{\sqrt{1-(\frac{v}{c})^2}}[/itex]

What I need to do now is solve for v using the given time and distance (.024 meters). The time is measured in the particle’s proper frame so:

t=(8.2*1011 seconds)[itex]\sqrt{1-(\frac{v}{c})^2}[/itex]

Of course, this contains v itself. What am I missing?

Thank you!

http://ift.tt/1c2VeLH

Leave a comment

Your email address will not be published.


*


Show Buttons
Hide Buttons