Find energy of a lightning strike

Consider the Earth and the cloud layer 800 meters above the earth to be the place of a parallel-plate capacitor. The cloud layer has an area of one kilometer squared. Assume this capacitor discharge that is lightning occurs, when the electric field strength between the plates reaches 3.0X10^6 V/m. What is the energy released if the capacitor discharge completely during a lightning strike?

Attempt:
C=(€*A)/d=((8.85*10^-12)(1*10^6m))/800=1.11*10^-8 F
Energy density=(0.5)(€)(E^2)=(.5)(8.85*10^-12)(3*10^6)^2=39.83=energy/volume therefore energy=39.83*(A*800)=3.19*10^10 J

Is this correctly done? Any help is appreciated.

http://ift.tt/1l2Kf4w

Leave a comment

Your email address will not be published.


*


Show Buttons
Hide Buttons