Two similar point charges q1 and q2 are placed at a distance r apart in the air. A dielectric slab of thickness t(<<r) having dielectric constant K is placed between the charges. Calculate the coulomb force of repulsion between the charges.
Now assume that a slab of thickness half the separation between the charges and the Coulomb’s repulsive force is reduced in the ratio 9:4. Calculate K for such a slab.
2. Relevant equations
Coulomb’s law :
3. The attempt at a solution
I am not sure. For such a system how should I apply Coulomb’s law ? We have a dielectric slab between the system. So how to make that law apply here ?
I just thought that I have to transform the given system to its equivalent vacuum one, but how should I do that ?
Please help !!
Thanks in advance…:smile: