# Dimensional analysis. Please check my working

**1. The problem statement, all variables and given/known data**

Two spheres are cut from a certain uniform rock. One has radius 4.30 cm. The mass of the other is six times greater. Find its radius.

**2. Relevant equations**

v = (4/3)(pi)(r)^3

m = vp

**3. The attempt at a solution**

6[(4/3)(pi)(r_{1})^{3}] = (4/3)(pi)(r_{2})^{3}

8(pi)(r_{1})3 = (4/3)(pi)(r_{2})3

6(r_{1})^{3} = (r_{2})^{3}

6(4.3)^{(1/3)} = 9.7568

Answer:

9.76 cm

I got this question wrong for some reason… Where is my mistake…?

http://ift.tt/P4rCT3

## Leave a comment