# Derivative Method for Error in Kinetic Energy formula

**1. The problem statement, all variables and given/known data**

Finding error in kinetic energy

**2. Relevant equations**

K = [itex]\frac{1}{2}[/itex] m v^{2}

**3. The attempt at a solution**

Measured mass and velocities have errors in them. So we have to use derivative method to calculate uncertainty in KE which is to find the square root of the derivatives of K with respect to m and v and multiply by the errors of the variable you took the derivative of.

[1] derivative of K with respect to m = 1/2 v^{2} times error in the mass

[2] derivative of K with respect to v = m v times error in the velocity

to calculate the error in K we have to take the square root of the addition of the square of [1] and square of [2].

What I don’t understand is why the units don’t match with equation [2]. Units should be kg^{2}m^{2}/s^{2}

http://ift.tt/1f3m3tG

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