Current Amplification Ratio

1. The problem statement, all variables and given/known data
If IB and IC (IB = Base current and IC = Collector current) of bipolar junction transistor are 1mA and 100 mA respectively, determine its current amplification ratio in common emitter configuration.

2. Relevant equations
IC=β*IB
Where β = current gain = [itex]\alpha[/itex]/([itex]\alpha[/itex]-1) (is this the same as current amplification ratio)???

Where [itex]\alpha[/itex] = IC/IE (IE = Emitter current)

3. The attempt at a solution
I understand that whatever signal is input in through the base is amplified out through the collector.

I found this page very helpful http://ift.tt/1dcVUMx

β = IC/IB = 100mA/10mA = 100

Was this problem really that easy?! Or am I missing something big here? Professor usually assigns pretty involved homework problems.

Thank you.

http://ift.tt/1eRWuM2

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