# Conservation of Energy

**1. The problem statement, all variables and given/known data**

A shot putter throws her shot. At the moment the 4.00 kg weight leaves her hand, it as a velocity of 14.0 m/s and is 2.00 m above the ground. The weight reaches a maximum height of 6.50 m above the ground before falling back down.

What is the magnitude of the weighted ball’s velocity at the peak of its trajectory?

**2. Relevant equations**

E_{k} = (0.5)(m)(v^{2})

E_{p} = (m)(g)(h)

**3. The attempt at a solution**

(0.5)(m)(v^{2}) _{initial }+ (m)(g)(h) _{initial} = (0.5)(m)(v^{2}) _{final}+ (m)(g)(h) _{final}

(0.5)( 14 m/s)^{2} + (2 m)(9.8 m/s^{2}) = (0.5)(v^{2}) + (9.8 m/s^{2})(6.5 m)

V_{peak} = 5.19 m/s

I don’t know if this is correct… isn’t the velocity at the peak supposed to be zero as all the energy is potential.

http://ift.tt/1qhqA6m

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