A shot putter throws her shot. At the moment the 4.00 kg weight leaves her hand, it as a velocity of 14.0 m/s and is 2.00 m above the ground. The weight reaches a maximum height of 6.50 m above the ground before falling back down.
What is the magnitude of the weighted ball’s velocity at the peak of its trajectory?
2. Relevant equations
Ek = (0.5)(m)(v2)
Ep = (m)(g)(h)
3. The attempt at a solution
(0.5)(m)(v2) initial + (m)(g)(h) initial = (0.5)(m)(v2) final+ (m)(g)(h) final
(0.5)( 14 m/s)2 + (2 m)(9.8 m/s2) = (0.5)(v2) + (9.8 m/s2)(6.5 m)
Vpeak = 5.19 m/s
I don’t know if this is correct… isn’t the velocity at the peak supposed to be zero as all the energy is potential.